{r^2}\) The constant of proportionality is the universal gravitational constant ("big G") which equals \(6.674\times{10^{- 11}}N{m^2}k{g^{- 2}}\). Overall this equation is simpler than it looks as ...

“The gravitational quantum metrological triangle may have applications in metrology and could be used to investigate the relation of the Planck constant to fundamental particle masses,” the ...

{2} a t^{2}\). No, the acceleration due to gravity is constant. Providing the object does not build up too much speed and air resistance is not a factor the acceleration measured should be the same.